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Shrink/Stretch calculation
Pattern Design_Advance_Shrink/Stretch:
When adding 10% shrinkage to 100cm, the result is 111,11cm.
What is the reason for this?
Why not 110cm?
Thanks a lot.

When adding 10% shrinkage to 100cm, the result is 111,11cm.
What is the reason for this?
Why not 110cm?
Thanks a lot.

Best Answers
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Vasyl Posts: 1,507 ✭✭✭✭
Mechelle сказав:Pattern Design_Advance_Shrink/Stretch:
When adding 10% shrinkage to 100cm, the result is 111,11cm.
What is the reason for this?
Why not 110cm?
Thanks a lot.))
Not confuse shrink with scale -
MuhammadOwais Posts: 445 ✭✭✭
@Mechelle
Shrinkage in a pattern means it gets smaller after a number of operations on the fabric. To counter this issue, We add shrinkage value to the pattern in advance, means We make it bigger to a certain amount in advance so when it shrinks, the resultant pattern becomes the actual required sized.
Now adding 10% shrinkage to a 100x100cm Box doesn't means to add a 10% of a 100cm (which is 10cm itself) to the pattern but to get the Resultant Pattern with a measurement of 100cm which is 10% smaller than the Actual Pattern.
So the AccuMark will make a pattern bigger with a factor of 10% of the actual pattern.
You can also calculate the value of Actual (Big) Pattern and If You love the math it'll be as follows:
Let say:
Actual Pattern = The Big pattern after adding shrinkage
Resultant Pattern = Pattern after shrinkage / pattern in which You've added shrinkage
%age = Shrinkage %age value
So:
=> Resultant Pattern = Actual Pattern - (Actual Pattern x %age)
=> Resultant Pattern = Actual Pattern - Actual Pattern x %age
Taking Actual Pattern as Common:
=> Resultant Pattern = Actual Pattern x (1 - %age)
=> Resultant Pattern / (1 - %age) = Actual Pattern
=> Actual Pattern = Resultant Pattern / (1 - %age)
Adding Values:
=> Actual Pattern = 100cm / (1 - 10%)
=> Actual Pattern = 100cm / 90%
=> Actual Pattern = 111.11cm
Hence the Method/Formula to calculate the Pattern measurement after adding shrinkage is just divide Your measurement by (1-%age).
This sounds so mathematical but someone might need it in the future...
Regards,
Owais...I'm a Cutting CAD Room Specialist and Technology Enthusiast...
Answers
Your explaination is very helpful and crystal clear. Honestly, I would not have figured that out by myself. I sincerely appreciate the advise. All the best to you. :-)